Property Detail

• java.lang.Object associationQueryHandlers

• java.util.Map<java.lang.String, java.util.Map> datastore

• java.lang.Object functionHandlers

• java.lang.Object handlers

Constructor Detail

• SimpleMapQuery(SimpleMapSession session, PersistentEntity entity, SimpleMapEntityPersister entityPersister)

Method Detail

• java.lang.Object executeAssociationSubQuery(java.lang.Object allEntities, PersistentEntity associatedEntity, Junction queryCriteria, PersistentProperty property)

• protected java.util.List executeLikeWithRegex(SimpleMapEntityPersister entityPersister, PersistentProperty property, java.lang.Object regexFormat)

• protected java.util.List executeQuery(PersistentEntity entity, Junction criteria)

• java.util.Map executeSubQuery(java.lang.Object criteria, java.lang.Object criteriaList)

• java.util.Collection executeSubQueryInternal(java.lang.Object criteria, java.lang.Object criteriaList)

• protected java.lang.String getFamily(PersistentEntity entity)

• protected PersistentProperty getValidProperty(java.lang.Object criterion)

• protected java.lang.Object populateQueryResult(java.lang.Object identifiers, java.util.Map queryResult)

• protected java.lang.Object queryAssociation(java.lang.Object allEntities, Association association, groovy.lang.Closure callable)

• protected java.lang.Object queryAssociationList(java.lang.Object allEntities, Association association, groovy.lang.Closure callable)

• protected java.lang.Object resolveIfEmbedded(java.lang.Object propertyName, java.lang.Object obj)

  If the property name refers to an embedded property like 'foo.startDate', then we need resolve the value of startDate by walking through the key list. @return

  Parameters:

  propertyName - the full property name

• protected java.lang.Object subqueryIfNecessary(PropertyCriterion pc, boolean uniqueResult)